Base | Representation |
---|---|
bin | 10011101101000001111… |
… | …001001010111111110011 |
3 | 11210102221222220011201010 |
4 | 103231001321022333303 |
5 | 134141013133021111 |
6 | 2514010040042003 |
7 | 166552611561141 |
oct | 23550171127763 |
9 | 4712858804633 |
10 | 1354020204531 |
11 | 482267119425 |
12 | 19a502763303 |
13 | 9a8b6a110c7 |
14 | 4976bbac591 |
15 | 2534b6d1aa6 |
hex | 13b41e4aff3 |
1354020204531 has 32 divisors (see below), whose sum is σ = 1864701538560. Its totient is φ = 873300714624.
The previous prime is 1354020204521. The next prime is 1354020204637.
1354020204531 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1354020204531 - 27 = 1354020204403 is a prime.
It is a super-2 number, since 2×13540202045312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1354020204521) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14360700 + ... + 14454678.
It is an arithmetic number, because the mean of its divisors is an integer number (58271923080).
Almost surely, 21354020204531 is an apocalyptic number.
1354020204531 is a deficient number, since it is larger than the sum of its proper divisors (510681334029).
1354020204531 is a wasteful number, since it uses less digits than its factorization.
1354020204531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94755.
The product of its (nonzero) digits is 14400, while the sum is 30.
It can be divided in two parts, 1354020 and 204531, that added together give a palindrome (1558551).
The spelling of 1354020204531 in words is "one trillion, three hundred fifty-four billion, twenty million, two hundred four thousand, five hundred thirty-one".
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