Base | Representation |
---|---|
bin | 11001001110001001… |
… | …01110101010101011 |
3 | 1021221122202021122120 |
4 | 30213010232222223 |
5 | 210212323444120 |
6 | 10115334522323 |
7 | 656354644314 |
oct | 144704565253 |
9 | 37848667576 |
10 | 13540453035 |
11 | 581926185a |
12 | 275a8063a3 |
13 | 137a34b8b5 |
14 | 92645160b |
15 | 543b0b140 |
hex | 32712eaab |
13540453035 has 16 divisors (see below), whose sum is σ = 21709222656. Its totient is φ = 7206742368.
The previous prime is 13540453033. The next prime is 13540453049. The reversal of 13540453035 is 53035404531.
It is not a de Polignac number, because 13540453035 - 21 = 13540453033 is a prime.
It is a super-2 number, since 2×135404530352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13540452987 and 13540453005.
It is not an unprimeable number, because it can be changed into a prime (13540453033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 919489 + ... + 934098.
It is an arithmetic number, because the mean of its divisors is an integer number (1356826416).
Almost surely, 213540453035 is an apocalyptic number.
13540453035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13540453035 is a deficient number, since it is larger than the sum of its proper divisors (8168769621).
13540453035 is a wasteful number, since it uses less digits than its factorization.
13540453035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1854082.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 13540453035 its reverse (53035404531), we get a palindrome (66575857566).
The spelling of 13540453035 in words is "thirteen billion, five hundred forty million, four hundred fifty-three thousand, thirty-five".
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