Base | Representation |
---|---|
bin | 10011101101000100000… |
… | …011101110011001011001 |
3 | 11210110001112020110120112 |
4 | 103231010003232121121 |
5 | 134141101432303101 |
6 | 2514013414334105 |
7 | 166553532363656 |
oct | 23550403563131 |
9 | 4713045213515 |
10 | 1354056525401 |
11 | 482285676878 |
12 | 19a51295a335 |
13 | 9a8c13ba148 |
14 | 49772944c2d |
15 | 2534e9a86bb |
hex | 13b440ee659 |
1354056525401 has 4 divisors (see below), whose sum is σ = 1363940149812. Its totient is φ = 1344172900992.
The previous prime is 1354056525379. The next prime is 1354056525421. The reversal of 1354056525401 is 1045256504531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 811954177225 + 542102348176 = 901085^2 + 736276^2 .
It is a cyclic number.
It is not a de Polignac number, because 1354056525401 - 26 = 1354056525337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1354056525421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4941812000 + ... + 4941812273.
It is an arithmetic number, because the mean of its divisors is an integer number (340985037453).
Almost surely, 21354056525401 is an apocalyptic number.
It is an amenable number.
1354056525401 is a deficient number, since it is larger than the sum of its proper divisors (9883624411).
1354056525401 is an equidigital number, since it uses as much as digits as its factorization.
1354056525401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9883624410.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 1354056525401 in words is "one trillion, three hundred fifty-four billion, fifty-six million, five hundred twenty-five thousand, four hundred one".
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