Base | Representation |
---|---|
bin | 111111000011100000… |
… | …1110111000110011010 |
3 | 110221111220200010220012 |
4 | 1332013001313012122 |
5 | 4204304301220140 |
6 | 142112313201522 |
7 | 12532366615334 |
oct | 1760701670632 |
9 | 427456603805 |
10 | 135409398170 |
11 | 52477091032 |
12 | 222b04002a2 |
13 | c9cc7b5657 |
14 | 67a7a9a454 |
15 | 37c7bd8265 |
hex | 1f8707719a |
135409398170 has 16 divisors (see below), whose sum is σ = 256565175840. Its totient is φ = 51313035024.
The previous prime is 135409398167. The next prime is 135409398191. The reversal of 135409398170 is 71893904531.
135409398170 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1354093981702 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 356340332 + ... + 356340711.
It is an arithmetic number, because the mean of its divisors is an integer number (16035323490).
Almost surely, 2135409398170 is an apocalyptic number.
135409398170 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135409398170 is a deficient number, since it is larger than the sum of its proper divisors (121155777670).
135409398170 is a wasteful number, since it uses less digits than its factorization.
135409398170 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 712681069.
The product of its (nonzero) digits is 816480, while the sum is 50.
The spelling of 135409398170 in words is "one hundred thirty-five billion, four hundred nine million, three hundred ninety-eight thousand, one hundred seventy".
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