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13541000353 = 311492931587
BaseRepresentation
bin11001001110001101…
…10100010010100001
31021221200210002102121
430213012310102201
5210212444002403
610115354344241
7656362414066
oct144706642241
937850702377
1013541000353
1158195a5a91
12275aa2b081
13137a4b0a5a
14926554c6d
15543bb83bd
hex3271b44a1

13541000353 has 8 divisors (see below), whose sum is σ = 14071622400. Its totient is φ = 13016241840.

The previous prime is 13541000339. The next prime is 13541000357. The reversal of 13541000353 is 35300014531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13541000353 - 221 = 13538903201 is a prime.

It is a super-2 number, since 2×135410003532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13541000357) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1461175 + ... + 1470412.

It is an arithmetic number, because the mean of its divisors is an integer number (1758952800).

Almost surely, 213541000353 is an apocalyptic number.

It is an amenable number.

13541000353 is a deficient number, since it is larger than the sum of its proper divisors (530622047).

13541000353 is a wasteful number, since it uses less digits than its factorization.

13541000353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2931767.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 13541000353 its reverse (35300014531), we get a palindrome (48841014884).

The spelling of 13541000353 in words is "thirteen billion, five hundred forty-one million, three hundred fifty-three", and thus it is an aban number.

Divisors: 1 31 149 4619 2931587 90879197 436806463 13541000353