Base | Representation |
---|---|
bin | 10011101101001001111… |
… | …000000110100111010001 |
3 | 11210110022022220220121002 |
4 | 103231021320012213101 |
5 | 134141301430022121 |
6 | 2514031222511345 |
7 | 166556126201642 |
oct | 23551170064721 |
9 | 4713268826532 |
10 | 1354154142161 |
11 | 48232578a787 |
12 | 19a53b595555 |
13 | 9a9086a7c42 |
14 | 497818b56c9 |
15 | 2535833be0b |
hex | 13b49e069d1 |
1354154142161 has 2 divisors, whose sum is σ = 1354154142162. Its totient is φ = 1354154142160.
The previous prime is 1354154142149. The next prime is 1354154142259. The reversal of 1354154142161 is 1612414514531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1354153469761 + 672400 = 1163681^2 + 820^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1354154142161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1354154142101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677077071080 + 677077071081.
It is an arithmetic number, because the mean of its divisors is an integer number (677077071081).
Almost surely, 21354154142161 is an apocalyptic number.
It is an amenable number.
1354154142161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354154142161 is an equidigital number, since it uses as much as digits as its factorization.
1354154142161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57600, while the sum is 38.
Adding to 1354154142161 its reverse (1612414514531), we get a palindrome (2966568656692).
The spelling of 1354154142161 in words is "one trillion, three hundred fifty-four billion, one hundred fifty-four million, one hundred forty-two thousand, one hundred sixty-one".
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