Base | Representation |
---|---|
bin | 11001001110010001… |
… | …11011100011110001 |
3 | 1021221201211020110111 |
4 | 30213020323203301 |
5 | 210213114220132 |
6 | 10115414301321 |
7 | 656400212326 |
oct | 144710734361 |
9 | 37851736414 |
10 | 13541554417 |
11 | 5819944296 |
12 | 275b057841 |
13 | 137a645cc1 |
14 | 92665ab4d |
15 | 543c77647 |
hex | 32723b8f1 |
13541554417 has 2 divisors, whose sum is σ = 13541554418. Its totient is φ = 13541554416.
The previous prime is 13541554393. The next prime is 13541554421. The reversal of 13541554417 is 71445514531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8076796641 + 5464757776 = 89871^2 + 73924^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13541554417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13541554417.
It is not a weakly prime, because it can be changed into another prime (13541554487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770777208 + 6770777209.
It is an arithmetic number, because the mean of its divisors is an integer number (6770777209).
Almost surely, 213541554417 is an apocalyptic number.
It is an amenable number.
13541554417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13541554417 is an equidigital number, since it uses as much as digits as its factorization.
13541554417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 168000, while the sum is 40.
The spelling of 13541554417 in words is "thirteen billion, five hundred forty-one million, five hundred fifty-four thousand, four hundred seventeen".
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