13541555403 has 8 divisors (see below), whose sum is σ = 20061563600. Its totient is φ = 9027703584.

The previous prime is 13541555393. The next prime is 13541555413. The reversal of 13541555403 is 30455514531.

13541555403 is a `hidden beast` number, since 13 + 54 + 1 + 55 + 540 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (13541555393) and next prime (13541555413).

It is not a de Polignac number, because 13541555403 - 2⁴ = 13541555387 is a prime.

It is a super-6 number, since 6×13541555403⁶ (a number of 62 digits) contains 666666 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13541555413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250769518 + ... + 250769571.

It is an arithmetic number, because the mean of its divisors is an integer number (2507695450).

Almost surely, 2^13541555403 is an apocalyptic number.

13541555403 is a deficient number, since it is larger than the sum of its proper divisors (6520008197).

13541555403 is an equidigital number, since it uses as much as digits as its factorization.

13541555403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501539098 (or 501539092 counting only the distinct ones).

The product of its (nonzero) digits is 90000, while the sum is 36.

The spelling of 13541555403 in words is "thirteen billion, five hundred forty-one million, five hundred fifty-five thousand, four hundred three".