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13542345041 = 37793583579
BaseRepresentation
bin11001001110010111…
…11100100101010001
31021221210022101222212
430213023330211101
5210213320020131
610115443241505
7656410014341
oct144713744521
937853271885
1013542345041
11581a3342a5
12275b379295
13137a861b24
149267c4d21
15543d81a2b
hex3272fc951

13542345041 has 4 divisors (see below), whose sum is σ = 13545932400. Its totient is φ = 13538757684.

The previous prime is 13542344987. The next prime is 13542345049. The reversal of 13542345041 is 14054324531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13542345041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13542344989 and 13542345007.

It is not an unprimeable number, because it can be changed into a prime (13542345049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1788011 + ... + 1795568.

It is an arithmetic number, because the mean of its divisors is an integer number (3386483100).

Almost surely, 213542345041 is an apocalyptic number.

It is an amenable number.

13542345041 is a deficient number, since it is larger than the sum of its proper divisors (3587359).

13542345041 is an equidigital number, since it uses as much as digits as its factorization.

13542345041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3587358.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13542345041 its reverse (14054324531), we get a palindrome (27596669572).

The spelling of 13542345041 in words is "thirteen billion, five hundred forty-two million, three hundred forty-five thousand, forty-one".

Divisors: 1 3779 3583579 13542345041