Base | Representation |
---|---|
bin | 1100010100010100011001… |
… | …0010110111010010111001 |
3 | 1202221201101200021101121012 |
4 | 3011011012102313102321 |
5 | 3233342444034000424 |
6 | 44445355414323305 |
7 | 2565315254042366 |
oct | 305050622672271 |
9 | 52851350241535 |
10 | 13543211234489 |
11 | 4351709742232 |
12 | 1628922059535 |
13 | 77317225b9a1 |
14 | 34b6d00c746d |
15 | 187453b6db0e |
hex | c51464b74b9 |
13543211234489 has 2 divisors, whose sum is σ = 13543211234490. Its totient is φ = 13543211234488.
The previous prime is 13543211234473. The next prime is 13543211234543. The reversal of 13543211234489 is 98443211234531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7831087334464 + 5712123900025 = 2798408^2 + 2390005^2 .
It is a cyclic number.
It is not a de Polignac number, because 13543211234489 - 24 = 13543211234473 is a prime.
It is a super-2 number, since 2×135432112344892 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13543211234419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771605617244 + 6771605617245.
It is an arithmetic number, because the mean of its divisors is an integer number (6771605617245).
Almost surely, 213543211234489 is an apocalyptic number.
It is an amenable number.
13543211234489 is a deficient number, since it is larger than the sum of its proper divisors (1).
13543211234489 is an equidigital number, since it uses as much as digits as its factorization.
13543211234489 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2488320, while the sum is 50.
The spelling of 13543211234489 in words is "thirteen trillion, five hundred forty-three billion, two hundred eleven million, two hundred thirty-four thousand, four hundred eighty-nine".
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