Base | Representation |
---|---|
bin | 10011101101010101001… |
… | …110000000101101100011 |
3 | 11210110210120222202122122 |
4 | 103231111032000231203 |
5 | 134142144133401111 |
6 | 2514102141254455 |
7 | 166563626515124 |
oct | 23552516005543 |
9 | 4713716882578 |
10 | 1354344434531 |
11 | 482413142200 |
12 | 19a59326442b |
13 | 9a938c4378a |
14 | 4979cc8c04b |
15 | 25369dc9cdb |
hex | 13b55380b63 |
1354344434531 has 12 divisors (see below), whose sum is σ = 1490468515536. Its totient is φ = 1229726105520.
The previous prime is 1354344434491. The next prime is 1354344434549.
1354344434531 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-1354344434531 is a prime.
It is a super-2 number, since 2×13543444345312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1354344436531) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6700496 + ... + 6899661.
It is an arithmetic number, because the mean of its divisors is an integer number (124205709628).
Almost surely, 21354344434531 is an apocalyptic number.
1354344434531 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1354344434531 is a deficient number, since it is larger than the sum of its proper divisors (136124081005).
1354344434531 is a wasteful number, since it uses less digits than its factorization.
1354344434531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13601002 (or 13600991 counting only the distinct ones).
The product of its digits is 2073600, while the sum is 44.
The spelling of 1354344434531 in words is "one trillion, three hundred fifty-four billion, three hundred forty-four million, four hundred thirty-four thousand, five hundred thirty-one".
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