Base | Representation |
---|---|
bin | 11110110010110101101011… |
… | …001000111010010110100011 |
3 | 122202112110102002201011020202 |
4 | 132302311223020322112203 |
5 | 120222431340304234133 |
6 | 1200013551452455415 |
7 | 40345566405056165 |
oct | 3662655310722643 |
9 | 582473362634222 |
10 | 135435001243043 |
11 | 3a176730467027 |
12 | 13234263a7a56b |
13 | 5a75609525188 |
14 | 2563136458935 |
15 | 109ce963dc2e8 |
hex | 7b2d6b23a5a3 |
135435001243043 has 2 divisors, whose sum is σ = 135435001243044. Its totient is φ = 135435001243042.
The previous prime is 135435001243027. The next prime is 135435001243093. The reversal of 135435001243043 is 340342100534531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135435001243043 - 24 = 135435001243027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135435001242988 and 135435001243006.
It is not a weakly prime, because it can be changed into another prime (135435001243013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67717500621521 + 67717500621522.
It is an arithmetic number, because the mean of its divisors is an integer number (67717500621522).
Almost surely, 2135435001243043 is an apocalyptic number.
135435001243043 is a deficient number, since it is larger than the sum of its proper divisors (1).
135435001243043 is an equidigital number, since it uses as much as digits as its factorization.
135435001243043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 135435001243043 its reverse (340342100534531), we get a palindrome (475777101777574).
The spelling of 135435001243043 in words is "one hundred thirty-five trillion, four hundred thirty-five billion, one million, two hundred forty-three thousand, forty-three".
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