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135436064201 is a prime number
BaseRepresentation
bin111111000100010011…
…1100101010111001001
3110221120202211220210222
41332020213211113021
54204333113023301
6142115104515425
712533142360014
oct1761047452711
9427522756728
10135436064201
1152490144679
12222b931bb75
13ca05190c79
1467ab43c37b
1537ca20431b
hex1f889e55c9

135436064201 has 2 divisors, whose sum is σ = 135436064202. Its totient is φ = 135436064200.

The previous prime is 135436064171. The next prime is 135436064237. The reversal of 135436064201 is 102460634531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133353510976 + 2082553225 = 365176^2 + 45635^2 .

It is a cyclic number.

It is not a de Polignac number, because 135436064201 - 210 = 135436063177 is a prime.

It is a super-3 number, since 3×1354360642013 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (135436064251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67718032100 + 67718032101.

It is an arithmetic number, because the mean of its divisors is an integer number (67718032101).

Almost surely, 2135436064201 is an apocalyptic number.

It is an amenable number.

135436064201 is a deficient number, since it is larger than the sum of its proper divisors (1).

135436064201 is an equidigital number, since it uses as much as digits as its factorization.

135436064201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 135436064201 its reverse (102460634531), we get a palindrome (237896698732).

The spelling of 135436064201 in words is "one hundred thirty-five billion, four hundred thirty-six million, sixty-four thousand, two hundred one".