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135440542234433 is a prime number
BaseRepresentation
bin11110110010111010110101…
…011010000111011101000001
3122202112222201021001200111002
4132302322311122013131001
5120223024212303000213
61200020305351301345
740346153616525062
oct3662726532073501
9582488637050432
10135440542234433
113a179014188957
121323534b67a855
135a75cb048b9c7
142563500302569
15109d1bcaa7658
hex7b2eb5687741

135440542234433 has 2 divisors, whose sum is σ = 135440542234434. Its totient is φ = 135440542234432.

The previous prime is 135440542234379. The next prime is 135440542234607. The reversal of 135440542234433 is 334432245044531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130968958323889 + 4471583910544 = 11444167^2 + 2114612^2 .

It is a cyclic number.

It is not a de Polignac number, because 135440542234433 - 226 = 135440475125569 is a prime.

It is not a weakly prime, because it can be changed into another prime (135440542233433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67720271117216 + 67720271117217.

It is an arithmetic number, because the mean of its divisors is an integer number (67720271117217).

Almost surely, 2135440542234433 is an apocalyptic number.

It is an amenable number.

135440542234433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135440542234433 is an equidigital number, since it uses as much as digits as its factorization.

135440542234433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8294400, while the sum is 47.

Adding to 135440542234433 its reverse (334432245044531), we get a palindrome (469872787278964).

The spelling of 135440542234433 in words is "one hundred thirty-five trillion, four hundred forty billion, five hundred forty-two million, two hundred thirty-four thousand, four hundred thirty-three".