Base | Representation |
---|---|
bin | 11001001110100100… |
… | …11110011001110001 |
3 | 1021221220112100120202 |
4 | 30213102132121301 |
5 | 210214234301213 |
6 | 10115544044545 |
7 | 656430402665 |
oct | 144722363161 |
9 | 37856470522 |
10 | 13544056433 |
11 | 58202a3076 |
12 | 275ba63755 |
13 | 137b010a9b |
14 | 926b0c8a5 |
15 | 5440bdb58 |
hex | 32749e671 |
13544056433 has 2 divisors, whose sum is σ = 13544056434. Its totient is φ = 13544056432.
The previous prime is 13544056429. The next prime is 13544056439. The reversal of 13544056433 is 33465044531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7329414544 + 6214641889 = 85612^2 + 78833^2 .
It is a cyclic number.
It is not a de Polignac number, because 13544056433 - 22 = 13544056429 is a prime.
It is a super-3 number, since 3×135440564333 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13544056439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6772028216 + 6772028217.
It is an arithmetic number, because the mean of its divisors is an integer number (6772028217).
Almost surely, 213544056433 is an apocalyptic number.
It is an amenable number.
13544056433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13544056433 is an equidigital number, since it uses as much as digits as its factorization.
13544056433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
The spelling of 13544056433 in words is "thirteen billion, five hundred forty-four million, fifty-six thousand, four hundred thirty-three".
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