Base | Representation |
---|---|
bin | 1100010100010111110010… |
… | …0101001101101011000100 |
3 | 1202221210202011001210202122 |
4 | 3011011330211031223010 |
5 | 3233401330213430104 |
6 | 44450030031425112 |
7 | 2565346653406412 |
oct | 305057445155304 |
9 | 52853664053678 |
10 | 13544122014404 |
11 | 4352036867703 |
12 | 1628b37085198 |
13 | 773288b5ac07 |
14 | 34b77904c2b2 |
15 | 1874a8ac96be |
hex | c517c94dac4 |
13544122014404 has 6 divisors (see below), whose sum is σ = 23702213525214. Its totient is φ = 6772061007200.
The previous prime is 13544122014331. The next prime is 13544122014427. The reversal of 13544122014404 is 40441022144531.
It can be written as a sum of positive squares in only one way, i.e., 10885037365504 + 2659084648900 = 3299248^2 + 1630670^2 .
It is a super-2 number, since 2×135441220144042 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1693015251797 + ... + 1693015251804.
It is an arithmetic number, because the mean of its divisors is an integer number (3950368920869).
Almost surely, 213544122014404 is an apocalyptic number.
It is an amenable number.
13544122014404 is a deficient number, since it is larger than the sum of its proper divisors (10158091510810).
13544122014404 is a wasteful number, since it uses less digits than its factorization.
13544122014404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3386030503605 (or 3386030503603 counting only the distinct ones).
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 13544122014404 its reverse (40441022144531), we get a palindrome (53985144158935).
The spelling of 13544122014404 in words is "thirteen trillion, five hundred forty-four billion, one hundred twenty-two million, fourteen thousand, four hundred four".
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