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135445212441169 is a prime number
BaseRepresentation
bin11110110010111111001011…
…110001100010101001010001
3122202120102202201212202201221
4132302333023301202221101
5120223113243341104134
61200022401022125041
740346410425605131
oct3662771361425121
9582512681782657
10135445212441169
113a17aaa0412344
1213236233720781
135a76575bba947
142563824676ac1
15109d392ab75b4
hex7b2fcbc62a51

135445212441169 has 2 divisors, whose sum is σ = 135445212441170. Its totient is φ = 135445212441168.

The previous prime is 135445212441101. The next prime is 135445212441193. The reversal of 135445212441169 is 961144212544531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117892363730625 + 17552848710544 = 10857825^2 + 4189612^2 .

It is a cyclic number.

It is not a de Polignac number, because 135445212441169 - 213 = 135445212432977 is a prime.

It is a super-2 number, since 2×1354452124411692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135445212441569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67722606220584 + 67722606220585.

It is an arithmetic number, because the mean of its divisors is an integer number (67722606220585).

Almost surely, 2135445212441169 is an apocalyptic number.

It is an amenable number.

135445212441169 is a deficient number, since it is larger than the sum of its proper divisors (1).

135445212441169 is an equidigital number, since it uses as much as digits as its factorization.

135445212441169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4147200, while the sum is 52.

The spelling of 135445212441169 in words is "one hundred thirty-five trillion, four hundred forty-five billion, two hundred twelve million, four hundred forty-one thousand, one hundred sixty-nine".