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1354703061721 is a prime number
BaseRepresentation
bin10011101101101010100…
…110000100001011011001
311210111201120210220200011
4103231222212010023121
5134143412440433341
62514201512041521
7166605543013342
oct23555246041331
94714646726604
101354703061721
1148258761a109
1219a6733932a1
139a99532a709
14497d47630c9
152538b619b81
hex13b6a9842d9

1354703061721 has 2 divisors, whose sum is σ = 1354703061722. Its totient is φ = 1354703061720.

The previous prime is 1354703061713. The next prime is 1354703061727. The reversal of 1354703061721 is 1271603074531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1269576830025 + 85126231696 = 1126755^2 + 291764^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354703061721 - 23 = 1354703061713 is a prime.

It is not a weakly prime, because it can be changed into another prime (1354703061727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677351530860 + 677351530861.

It is an arithmetic number, because the mean of its divisors is an integer number (677351530861).

Almost surely, 21354703061721 is an apocalyptic number.

It is an amenable number.

1354703061721 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354703061721 is an equidigital number, since it uses as much as digits as its factorization.

1354703061721 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105840, while the sum is 40.

The spelling of 1354703061721 in words is "one trillion, three hundred fifty-four billion, seven hundred three million, sixty-one thousand, seven hundred twenty-one".