135473654147 has 32 divisors (see below), whose sum is σ = 150370698240. Its totient is φ = 121255706880.

The previous prime is 135473654123. The next prime is 135473654153. The reversal of 135473654147 is 741456374531.

It is a cyclic number.

It is not a de Polignac number, because 135473654147 - 2¹² = 135473650051 is a prime.

It is a super-2 number, since 2×135473654147² (a number of 23 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (50) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135473654095 and 135473654104.

It is not an unprimeable number, because it can be changed into a prime (135473654167) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 120634928 + ... + 120636050.

It is an arithmetic number, because the mean of its divisors is an integer number (4699084320).

Almost surely, 2^135473654147 is an apocalyptic number.

135473654147 is a deficient number, since it is larger than the sum of its proper divisors (14897044093).

135473654147 is a wasteful number, since it uses less digits than its factorization.

135473654147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2363.

The product of its digits is 4233600, while the sum is 50.

The spelling of 135473654147 in words is "one hundred thirty-five billion, four hundred seventy-three million, six hundred fifty-four thousand, one hundred forty-seven".