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135475633125000 = 23325776789577
BaseRepresentation
bin11110110011011011100000…
…111111001111011010001000
3122202200100021210202121211200
4132303123200333033122020
5120224113044040000000
61200044351403024200
740351535324263350
oct3663334077173210
9582610253677750
10135475633125000
113a191991069363
121324010350b060
135a793b3486a8c
1425650ac90bb60
15109e0735dd500
hex7b36e0fcf688

135475633125000 has 1536 divisors, whose sum is σ = 538893307929600. Its totient is φ = 30108672000000.

The previous prime is 135475633124947. The next prime is 135475633125061. The reversal of 135475633125000 is 521336574531.

135475633125000 is a `hidden beast` number, since 1 + 3 + 5 + 4 + 7 + 5 + 633 + 1 + 2 + 5 + 0 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 234793124712 + ... + 234793125288.

It is an arithmetic number, because the mean of its divisors is an integer number (350841997350).

Almost surely, 2135475633125000 is an apocalyptic number.

135475633125000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135475633125000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (269446653964800).

135475633125000 is an abundant number, since it is smaller than the sum of its proper divisors (403417674804600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135475633125000 is an frugal number, since it uses more digits than its factorization.

135475633125000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 787 (or 750 counting only the distinct ones).

The product of its (nonzero) digits is 1134000, while the sum is 45.

Adding to 135475633125000 its reverse (521336574531), we get a palindrome (135996969699531).

The spelling of 135475633125000 in words is "one hundred thirty-five trillion, four hundred seventy-five billion, six hundred thirty-three million, one hundred twenty-five thousand".