Search a number
-
+
135489444193 is a prime number
BaseRepresentation
bin111111000101111001…
…1001101100101100001
3110221201111021220101201
41332023303031211201
54204440244203233
6142124253001201
712534361162555
oct1761363154541
9427644256351
10135489444193
1152508293874
1222313183201
13ca1326096c
1467b4575865
1537cec4a77d
hex1f8bccd961

135489444193 has 2 divisors, whose sum is σ = 135489444194. Its totient is φ = 135489444192.

The previous prime is 135489444173. The next prime is 135489444241. The reversal of 135489444193 is 391444984531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79041386449 + 56448057744 = 281143^2 + 237588^2 .

It is a cyclic number.

It is not a de Polignac number, because 135489444193 - 213 = 135489436001 is a prime.

It is a super-2 number, since 2×1354894441932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135489444133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67744722096 + 67744722097.

It is an arithmetic number, because the mean of its divisors is an integer number (67744722097).

Almost surely, 2135489444193 is an apocalyptic number.

It is an amenable number.

135489444193 is a deficient number, since it is larger than the sum of its proper divisors (1).

135489444193 is an equidigital number, since it uses as much as digits as its factorization.

135489444193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7464960, while the sum is 55.

The spelling of 135489444193 in words is "one hundred thirty-five billion, four hundred eighty-nine million, four hundred forty-four thousand, one hundred ninety-three".