Base | Representation |
---|---|
bin | 11001001111011011… |
… | …01111110000111001 |
3 | 1021222101222120011112 |
4 | 30213231233300321 |
5 | 210223102033213 |
6 | 10120401210105 |
7 | 656545226363 |
oct | 144755576071 |
9 | 37871876145 |
10 | 13551205433 |
11 | 5824336237 |
12 | 2762330935 |
13 | 137c644a6c |
14 | 927a4dd33 |
15 | 544a31ea8 |
hex | 327b6fc39 |
13551205433 has 2 divisors, whose sum is σ = 13551205434. Its totient is φ = 13551205432.
The previous prime is 13551205417. The next prime is 13551205457. The reversal of 13551205433 is 33450215531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13250772544 + 300432889 = 115112^2 + 17333^2 .
It is a cyclic number.
It is not a de Polignac number, because 13551205433 - 24 = 13551205417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13551205433.
It is not a weakly prime, because it can be changed into another prime (13551205483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775602716 + 6775602717.
It is an arithmetic number, because the mean of its divisors is an integer number (6775602717).
Almost surely, 213551205433 is an apocalyptic number.
It is an amenable number.
13551205433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13551205433 is an equidigital number, since it uses as much as digits as its factorization.
13551205433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 32.
The spelling of 13551205433 in words is "thirteen billion, five hundred fifty-one million, two hundred five thousand, four hundred thirty-three".
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