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135512421243091 is a prime number
BaseRepresentation
bin11110110011111101110001…
…101110110001100011010011
3122202210212020122002122122221
4132303331301232301203103
5120230213414314234331
61200113314044041511
740354310061156064
oct3663756156614323
9582725218078587
10135512421243091
113a1a6549a98a42
121324726b833297
135a7c9c6c9a4a9
142566b9c6ba56b
15109eec812b711
hex7b3f71bb18d3

135512421243091 has 2 divisors, whose sum is σ = 135512421243092. Its totient is φ = 135512421243090.

The previous prime is 135512421242917. The next prime is 135512421243161. The reversal of 135512421243091 is 190342124215531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135512421243091 - 215 = 135512421210323 is a prime.

It is a super-2 number, since 2×1355124212430912 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135518421243091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67756210621545 + 67756210621546.

It is an arithmetic number, because the mean of its divisors is an integer number (67756210621546).

Almost surely, 2135512421243091 is an apocalyptic number.

135512421243091 is a deficient number, since it is larger than the sum of its proper divisors (1).

135512421243091 is an equidigital number, since it uses as much as digits as its factorization.

135512421243091 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 135512421243091 in words is "one hundred thirty-five trillion, five hundred twelve billion, four hundred twenty-one million, two hundred forty-three thousand, ninety-one".