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135514433 is a prime number
BaseRepresentation
bin10000001001111…
…00100101000001
3100102222211212002
420010330211001
5234142430213
621240313345
73233565545
oct1004744501
9312884762
10135514433
116a548aaa
1239472855
13220c9772
1413dd7a25
15bd6c658
hex813c941

135514433 has 2 divisors, whose sum is σ = 135514434. Its totient is φ = 135514432.

The previous prime is 135514417. The next prime is 135514439. The reversal of 135514433 is 334415531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97851664 + 37662769 = 9892^2 + 6137^2 .

It is a cyclic number.

It is not a de Polignac number, because 135514433 - 24 = 135514417 is a prime.

It is a super-2 number, since 2×1355144332 = 36728323102622978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135514396 and 135514405.

It is not a weakly prime, because it can be changed into another prime (135514439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67757216 + 67757217.

It is an arithmetic number, because the mean of its divisors is an integer number (67757217).

Almost surely, 2135514433 is an apocalyptic number.

It is an amenable number.

135514433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135514433 is an equidigital number, since it uses as much as digits as its factorization.

135514433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10800, while the sum is 29.

The square root of 135514433 is about 11641.0666607489. The cubic root of 135514433 is about 513.6435640452.

Adding to 135514433 its reverse (334415531), we get a palindrome (469929964).

The spelling of 135514433 in words is "one hundred thirty-five million, five hundred fourteen thousand, four hundred thirty-three".