Base | Representation |
---|---|
bin | 111111000110101100… |
… | …0010100010100010011 |
3 | 110221210100011110012120 |
4 | 1332031120110110103 |
5 | 4210014040321212 |
6 | 142131041025323 |
7 | 12535132361205 |
oct | 1761530242423 |
9 | 427710143176 |
10 | 135515948307 |
11 | 525212467a3 |
12 | 22320025243 |
13 | ca188b067c |
14 | 67b7cb4775 |
15 | 37d223388c |
hex | 1f8d614513 |
135515948307 has 16 divisors (see below), whose sum is σ = 191635006752. Its totient is φ = 84888115200.
The previous prime is 135515948287. The next prime is 135515948311. The reversal of 135515948307 is 703849515531.
It is not a de Polignac number, because 135515948307 - 27 = 135515948179 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 135515948307.
It is not an unprimeable number, because it can be changed into a prime (135515948377) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2179978 + ... + 2241279.
It is an arithmetic number, because the mean of its divisors is an integer number (11977187922).
Almost surely, 2135515948307 is an apocalyptic number.
135515948307 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
135515948307 is a deficient number, since it is larger than the sum of its proper divisors (56119058445).
135515948307 is a wasteful number, since it uses less digits than its factorization.
135515948307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4421878.
The product of its (nonzero) digits is 2268000, while the sum is 51.
The spelling of 135515948307 in words is "one hundred thirty-five billion, five hundred fifteen million, nine hundred forty-eight thousand, three hundred seven".
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