Base | Representation |
---|---|
bin | 10011101110001010100… |
… | …111111110010101101010 |
3 | 11210120010000222012111012 |
4 | 103232022213332111222 |
5 | 134201013022324002 |
6 | 2514331105503522 |
7 | 166625056416431 |
oct | 23561247762552 |
9 | 4716100865435 |
10 | 1355240433002 |
11 | 482832991105 |
12 | 19a7a3341ba2 |
13 | 9aa4c7689a1 |
14 | 49845c86118 |
15 | 253bd8b5d52 |
hex | 13b8a9fe56a |
1355240433002 has 4 divisors (see below), whose sum is σ = 2032860649506. Its totient is φ = 677620216500.
The previous prime is 1355240432999. The next prime is 1355240433023. The reversal of 1355240433002 is 2003340425531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1347296454361 + 7943978641 = 1160731^2 + 89129^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 1355240433002.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 338810108249 + ... + 338810108252.
Almost surely, 21355240433002 is an apocalyptic number.
1355240433002 is a deficient number, since it is larger than the sum of its proper divisors (677620216504).
1355240433002 is an equidigital number, since it uses as much as digits as its factorization.
1355240433002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 677620216503.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 1355240433002 its reverse (2003340425531), we get a palindrome (3358580858533).
The spelling of 1355240433002 in words is "one trillion, three hundred fifty-five billion, two hundred forty million, four hundred thirty-three thousand, two".
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