Base | Representation |
---|---|
bin | 1100010100111001000001… |
… | …0010010100110110110011 |
3 | 1202222122202211121120010201 |
4 | 3011032100102110312303 |
5 | 3234023112342321003 |
6 | 44454103133340031 |
7 | 2566114012552456 |
oct | 305162022246663 |
9 | 52878684546121 |
10 | 13553042542003 |
11 | 43558a4208068 |
12 | 162a806637617 |
13 | 77407b004003 |
14 | 34bd83a9749d |
15 | 18782bd08b1d |
hex | c5390494db3 |
13553042542003 has 4 divisors (see below), whose sum is σ = 13684625479408. Its totient is φ = 13421459604600.
The previous prime is 13553042541977. The next prime is 13553042542021. The reversal of 13553042542003 is 30024524035531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13553042542003 - 25 = 13553042541971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13553042542043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65791468548 + ... + 65791468753.
It is an arithmetic number, because the mean of its divisors is an integer number (3421156369852).
Almost surely, 213553042542003 is an apocalyptic number.
13553042542003 is a deficient number, since it is larger than the sum of its proper divisors (131582937405).
13553042542003 is a wasteful number, since it uses less digits than its factorization.
13553042542003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131582937404.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 13553042542003 its reverse (30024524035531), we get a palindrome (43577566577534).
The spelling of 13553042542003 in words is "thirteen trillion, five hundred fifty-three billion, forty-two million, five hundred forty-two thousand, three".
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