135531351210433 has 2 divisors, whose sum is σ = 135531351210434. Its totient is φ = 135531351210432.

The previous prime is 135531351210191. The next prime is 135531351210439. The reversal of 135531351210433 is 334012153135531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109858655897104 + 25672695313329 = 10481348^2 + 5066823^2 .

It is a cyclic number.

It is not a de Polignac number, because 135531351210433 - 2²⁹ = 135530814339521 is a prime.

It is a super-2 number, since 2×135531351210433² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135531351210439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67765675605216 + 67765675605217.

It is an arithmetic number, because the mean of its divisors is an integer number (67765675605217).

Almost surely, 2^{135531351210433} is an apocalyptic number.

It is an amenable number.

135531351210433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135531351210433 is an equidigital number, since it uses as much as digits as its factorization.

135531351210433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 40.

The spelling of 135531351210433 in words is "one hundred thirty-five trillion, five hundred thirty-one billion, three hundred fifty-one million, two hundred ten thousand, four hundred thirty-three".