Base | Representation |
---|---|
bin | 1100010100111001101100… |
… | …0011001001010101010111 |
3 | 1202222200020102101110122020 |
4 | 3011032123003021111113 |
5 | 3234024000104041043 |
6 | 44454133103504223 |
7 | 2566121334433620 |
oct | 305163303112527 |
9 | 52880212343566 |
10 | 13553223112023 |
11 | 4355987129a91 |
12 | 162a856bb8073 |
13 | 7740a954748a |
14 | 34bd9da5ca47 |
15 | 18783cac5e83 |
hex | c539b0c9557 |
13553223112023 has 32 divisors (see below), whose sum is σ = 21023541550080. Its totient is φ = 7605962242560.
The previous prime is 13553223112021. The next prime is 13553223112063. The reversal of 13553223112023 is 32021132235531.
13553223112023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13553223112023 - 21 = 13553223112021 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13553223112021) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7347538 + ... + 9005151.
It is an arithmetic number, because the mean of its divisors is an integer number (656985673440).
Almost surely, 213553223112023 is an apocalyptic number.
13553223112023 is a deficient number, since it is larger than the sum of its proper divisors (7470318438057).
13553223112023 is a wasteful number, since it uses less digits than its factorization.
13553223112023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16353407.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13553223112023 its reverse (32021132235531), we get a palindrome (45574355347554).
The spelling of 13553223112023 in words is "thirteen trillion, five hundred fifty-three billion, two hundred twenty-three million, one hundred twelve thousand, twenty-three".
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