Base | Representation |
---|---|
bin | 10011101110010000000… |
… | …111101100001000111111 |
3 | 11210120100110110110022112 |
4 | 103232100013230020333 |
5 | 134201210123230101 |
6 | 2514344202004235 |
7 | 166630256204510 |
oct | 23562007541077 |
9 | 4716313413275 |
10 | 1355332633151 |
11 | 48287aa35482 |
12 | 19a80a1a667b |
13 | 9aa658ab1a3 |
14 | 49854206a07 |
15 | 253c6a296bb |
hex | 13b901ec23f |
1355332633151 has 16 divisors (see below), whose sum is σ = 1598958704640. Its totient is φ = 1124210262240.
The previous prime is 1355332633141. The next prime is 1355332633183. The reversal of 1355332633151 is 1513362335531.
It is a cyclic number.
It is not a de Polignac number, because 1355332633151 - 210 = 1355332632127 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1355332633099 and 1355332633108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355332633141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14657180 + ... + 14749358.
It is an arithmetic number, because the mean of its divisors is an integer number (99934919040).
Almost surely, 21355332633151 is an apocalyptic number.
1355332633151 is a deficient number, since it is larger than the sum of its proper divisors (243626071489).
1355332633151 is an equidigital number, since it uses as much as digits as its factorization.
1355332633151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159974.
The product of its digits is 364500, while the sum is 41.
Adding to 1355332633151 its reverse (1513362335531), we get a palindrome (2868694968682).
The spelling of 1355332633151 in words is "one trillion, three hundred fifty-five billion, three hundred thirty-two million, six hundred thirty-three thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •