Base | Representation |
---|---|
bin | 11110110100010010010001… |
… | …000011111100101100111011 |
3 | 122202212222000212212212202211 |
4 | 132310102101003330230323 |
5 | 120231043443430131323 |
6 | 1200131353114435551 |
7 | 40356016214156533 |
oct | 3664222103745473 |
9 | 582788025785684 |
10 | 135534421723963 |
11 | 3a204909762939 |
12 | 1324b58b732bb7 |
13 | 5a81ac1c5a302 |
14 | 2567c885444c3 |
15 | 10a086480270d |
hex | 7b44910fcb3b |
135534421723963 has 2 divisors, whose sum is σ = 135534421723964. Its totient is φ = 135534421723962.
The previous prime is 135534421723957. The next prime is 135534421724027. The reversal of 135534421723963 is 369327124435531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135534421723963 - 217 = 135534421592891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135534421723898 and 135534421723907.
It is not a weakly prime, because it can be changed into another prime (135534421720963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767210861981 + 67767210861982.
It is an arithmetic number, because the mean of its divisors is an integer number (67767210861982).
Almost surely, 2135534421723963 is an apocalyptic number.
135534421723963 is a deficient number, since it is larger than the sum of its proper divisors (1).
135534421723963 is an equidigital number, since it uses as much as digits as its factorization.
135534421723963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48988800, while the sum is 58.
The spelling of 135534421723963 in words is "one hundred thirty-five trillion, five hundred thirty-four billion, four hundred twenty-one million, seven hundred twenty-three thousand, nine hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •