Base | Representation |
---|---|
bin | 10011101110010101010… |
… | …111010010111100011011 |
3 | 11210120120121000011022121 |
4 | 103232111113102330123 |
5 | 134201400134012311 |
6 | 2514401023402111 |
7 | 166632405043654 |
oct | 23562527227433 |
9 | 4716517004277 |
10 | 1355420610331 |
11 | 482915664a97 |
12 | 19a833753337 |
13 | 9aa7aba24a8 |
14 | 49861b8852b |
15 | 253ce606b71 |
hex | 13b955d2f1b |
1355420610331 has 2 divisors, whose sum is σ = 1355420610332. Its totient is φ = 1355420610330.
The previous prime is 1355420610319. The next prime is 1355420610409. The reversal of 1355420610331 is 1330160245531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1355420610331 is a prime.
It is a super-2 number, since 2×13554206103312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1355420611331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677710305165 + 677710305166.
It is an arithmetic number, because the mean of its divisors is an integer number (677710305166).
Almost surely, 21355420610331 is an apocalyptic number.
1355420610331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355420610331 is an equidigital number, since it uses as much as digits as its factorization.
1355420610331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 1355420610331 its reverse (1330160245531), we get a palindrome (2685580855862).
The spelling of 1355420610331 in words is "one trillion, three hundred fifty-five billion, four hundred twenty million, six hundred ten thousand, three hundred thirty-one".
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