Base | Representation |
---|---|
bin | 10011101110010110001… |
… | …000100000010100010001 |
3 | 11210120121111021112120002 |
4 | 103232112020200110101 |
5 | 134201411434311121 |
6 | 2514402204055345 |
7 | 166632622511543 |
oct | 23562610402421 |
9 | 4716544245502 |
10 | 1355433510161 |
11 | 482921975905 |
12 | 19a837b34555 |
13 | 9aa8076ac23 |
14 | 49863785693 |
15 | 253d0803e0b |
hex | 13b96220511 |
1355433510161 has 2 divisors, whose sum is σ = 1355433510162. Its totient is φ = 1355433510160.
The previous prime is 1355433510157. The next prime is 1355433510247. The reversal of 1355433510161 is 1610153345531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 757324619536 + 598108890625 = 870244^2 + 773375^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355433510161 - 22 = 1355433510157 is a prime.
It is not a weakly prime, because it can be changed into another prime (1355433510121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677716755080 + 677716755081.
It is an arithmetic number, because the mean of its divisors is an integer number (677716755081).
Almost surely, 21355433510161 is an apocalyptic number.
It is an amenable number.
1355433510161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355433510161 is an equidigital number, since it uses as much as digits as its factorization.
1355433510161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 38.
Adding to 1355433510161 its reverse (1610153345531), we get a palindrome (2965586855692).
The spelling of 1355433510161 in words is "one trillion, three hundred fifty-five billion, four hundred thirty-three million, five hundred ten thousand, one hundred sixty-one".
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