135550210010251 has 4 divisors (see below), whose sum is σ = 136361887914672. Its totient is φ = 134738532105832.

The previous prime is 135550210010249. The next prime is 135550210010269. The reversal of 135550210010251 is 152010012055531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135550210010251 - 2¹ = 135550210010249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135550210010051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405838951960 + ... + 405838952293.

It is an arithmetic number, because the mean of its divisors is an integer number (34090471978668).

Almost surely, 2^{135550210010251} is an apocalyptic number.

135550210010251 is a deficient number, since it is larger than the sum of its proper divisors (811677904421).

135550210010251 is an equidigital number, since it uses as much as digits as its factorization.

135550210010251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 811677904420.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 135550210010251 its reverse (152010012055531), we get a palindrome (287560222065782).

The spelling of 135550210010251 in words is "one hundred thirty-five trillion, five hundred fifty billion, two hundred ten million, ten thousand, two hundred fifty-one".