Base | Representation |
---|---|
bin | 1100010101000010100100… |
… | …0010100101100011010011 |
3 | 1202222220101102221200112112 |
4 | 3011100221002211203103 |
5 | 3234043334431031011 |
6 | 44455205323015535 |
7 | 2566234352110124 |
oct | 305205102454323 |
9 | 52886342850475 |
10 | 13555605330131 |
11 | 43569998a6787 |
12 | 162b20096a5ab |
13 | 774398c484a7 |
14 | 34c1481b004b |
15 | 18792bcd858b |
hex | c54290a58d3 |
13555605330131 has 2 divisors, whose sum is σ = 13555605330132. Its totient is φ = 13555605330130.
The previous prime is 13555605330097. The next prime is 13555605330149. The reversal of 13555605330131 is 13103350655531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13555605330131 is a prime.
It is a super-2 number, since 2×135556053301312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13555605330151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6777802665065 + 6777802665066.
It is an arithmetic number, because the mean of its divisors is an integer number (6777802665066).
Almost surely, 213555605330131 is an apocalyptic number.
13555605330131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13555605330131 is an equidigital number, since it uses as much as digits as its factorization.
13555605330131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 303750, while the sum is 41.
Adding to 13555605330131 its reverse (13103350655531), we get a palindrome (26658955985662).
The spelling of 13555605330131 in words is "thirteen trillion, five hundred fifty-five billion, six hundred five million, three hundred thirty thousand, one hundred thirty-one".
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