Base | Representation |
---|---|
bin | 111111000111111010… |
… | …1000001000101010011 |
3 | 110221220012110102101110 |
4 | 1332033311001011103 |
5 | 4210110044314011 |
6 | 142135105304403 |
7 | 12536141465502 |
oct | 1761765010523 |
9 | 427805412343 |
10 | 135557026131 |
11 | 5254245310a |
12 | 22331935103 |
13 | ca24263987 |
14 | 67bd528839 |
15 | 37d5b49ba6 |
hex | 1f8fd41153 |
135557026131 has 4 divisors (see below), whose sum is σ = 180742701512. Its totient is φ = 90371350752.
The previous prime is 135557026109. The next prime is 135557026147. The reversal of 135557026131 is 131620755531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131620755531 = 3 ⋅43873585177.
It is not a de Polignac number, because 135557026131 - 221 = 135554928979 is a prime.
It is a super-2 number, since 2×1355570261312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 135557026131.
It is not an unprimeable number, because it can be changed into a prime (135557096131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22592837686 + ... + 22592837691.
It is an arithmetic number, because the mean of its divisors is an integer number (45185675378).
Almost surely, 2135557026131 is an apocalyptic number.
135557026131 is a deficient number, since it is larger than the sum of its proper divisors (45185675381).
135557026131 is an equidigital number, since it uses as much as digits as its factorization.
135557026131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45185675380.
The product of its (nonzero) digits is 94500, while the sum is 39.
The spelling of 135557026131 in words is "one hundred thirty-five billion, five hundred fifty-seven million, twenty-six thousand, one hundred thirty-one".
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