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13557645333161 is a prime number
BaseRepresentation
bin1100010101001010001010…
…1000100101001010101001
31210000002122121120120121022
43011102202220211022221
53234112024201130121
644500143555222225
72566336042621616
oct305224250451251
953002577516538
1013557645333161
1143578463861a6
12162b68bba7975
1377463278a887
1434c29d0bd50d
151879eae4daab
hexc54a2a252a9

13557645333161 has 2 divisors, whose sum is σ = 13557645333162. Its totient is φ = 13557645333160.

The previous prime is 13557645333157. The next prime is 13557645333299. The reversal of 13557645333161 is 16133354675531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10175742723136 + 3381902610025 = 3189944^2 + 1838995^2 .

It is an emirp because it is prime and its reverse (16133354675531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13557645333161 - 22 = 13557645333157 is a prime.

It is not a weakly prime, because it can be changed into another prime (13557645333101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6778822666580 + 6778822666581.

It is an arithmetic number, because the mean of its divisors is an integer number (6778822666581).

Almost surely, 213557645333161 is an apocalyptic number.

It is an amenable number.

13557645333161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13557645333161 is an equidigital number, since it uses as much as digits as its factorization.

13557645333161 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10206000, while the sum is 53.

The spelling of 13557645333161 in words is "thirteen trillion, five hundred fifty-seven billion, six hundred forty-five million, three hundred thirty-three thousand, one hundred sixty-one".