Base | Representation |
---|---|
bin | 1100010101001010001010… |
… | …1000100101001010101001 |
3 | 1210000002122121120120121022 |
4 | 3011102202220211022221 |
5 | 3234112024201130121 |
6 | 44500143555222225 |
7 | 2566336042621616 |
oct | 305224250451251 |
9 | 53002577516538 |
10 | 13557645333161 |
11 | 43578463861a6 |
12 | 162b68bba7975 |
13 | 77463278a887 |
14 | 34c29d0bd50d |
15 | 1879eae4daab |
hex | c54a2a252a9 |
13557645333161 has 2 divisors, whose sum is σ = 13557645333162. Its totient is φ = 13557645333160.
The previous prime is 13557645333157. The next prime is 13557645333299. The reversal of 13557645333161 is 16133354675531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10175742723136 + 3381902610025 = 3189944^2 + 1838995^2 .
It is an emirp because it is prime and its reverse (16133354675531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13557645333161 - 22 = 13557645333157 is a prime.
It is not a weakly prime, because it can be changed into another prime (13557645333101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6778822666580 + 6778822666581.
It is an arithmetic number, because the mean of its divisors is an integer number (6778822666581).
Almost surely, 213557645333161 is an apocalyptic number.
It is an amenable number.
13557645333161 is a deficient number, since it is larger than the sum of its proper divisors (1).
13557645333161 is an equidigital number, since it uses as much as digits as its factorization.
13557645333161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10206000, while the sum is 53.
The spelling of 13557645333161 in words is "thirteen trillion, five hundred fifty-seven billion, six hundred forty-five million, three hundred thirty-three thousand, one hundred sixty-one".
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