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13560342545142 = 232192931288715277
BaseRepresentation
bin1100010101010100001101…
…1001101000001011110110
31210000100121120212010212100
43011111003121220023312
53234133040142421032
644501311350002530
72566462633553451
oct305250331501366
953010546763770
1013560342545142
1143589aa938508
121630103346446
137749725092b3
1434c4773c8498
15187b07b3297c
hexc55436682f6

13560342545142 has 192 divisors, whose sum is σ = 33039200563200. Its totient is φ = 3999530545920.

The previous prime is 13560342545137. The next prime is 13560342545177. The reversal of 13560342545142 is 24154524306531.

13560342545142 is a `hidden beast` number, since 1 + 3 + 5 + 60 + 3 + 4 + 2 + 545 + 1 + 42 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 887623608 + ... + 887638884.

It is an arithmetic number, because the mean of its divisors is an integer number (172079169600).

Almost surely, 213560342545142 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13560342545142, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16519600281600).

13560342545142 is an abundant number, since it is smaller than the sum of its proper divisors (19478858018058).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13560342545142 is a wasteful number, since it uses less digits than its factorization.

13560342545142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18251 (or 18248 counting only the distinct ones).

The product of its (nonzero) digits is 1728000, while the sum is 45.

The spelling of 13560342545142 in words is "thirteen trillion, five hundred sixty billion, three hundred forty-two million, five hundred forty-five thousand, one hundred forty-two".