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135617220257 is a prime number
BaseRepresentation
bin111111001001101101…
…0101000111010100001
3110222001101201121012112
41332103122220322201
54210221002022012
6142145055405105
712540502231541
oct1762332507241
9428041647175
10135617220257
1152573426922
1222349b23795
13ca3387b0bc
1467c7517321
1537db08a122
hex1f936a8ea1

135617220257 has 2 divisors, whose sum is σ = 135617220258. Its totient is φ = 135617220256.

The previous prime is 135617220191. The next prime is 135617220289. The reversal of 135617220257 is 752022716531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133988209936 + 1629010321 = 366044^2 + 40361^2 .

It is a cyclic number.

It is not a de Polignac number, because 135617220257 - 210 = 135617219233 is a prime.

It is a super-2 number, since 2×1356172202572 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135617210257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67808610128 + 67808610129.

It is an arithmetic number, because the mean of its divisors is an integer number (67808610129).

Almost surely, 2135617220257 is an apocalyptic number.

It is an amenable number.

135617220257 is a deficient number, since it is larger than the sum of its proper divisors (1).

135617220257 is an equidigital number, since it uses as much as digits as its factorization.

135617220257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 176400, while the sum is 41.

Adding to 135617220257 its reverse (752022716531), we get a palindrome (887639936788).

The spelling of 135617220257 in words is "one hundred thirty-five billion, six hundred seventeen million, two hundred twenty thousand, two hundred fifty-seven".