Base | Representation |
---|---|
bin | 11110110101100101111010… |
… | …111110011110011000010011 |
3 | 122210012112212212011122212121 |
4 | 132311211322332132120103 |
5 | 120234031423322103012 |
6 | 1200240530202035111 |
7 | 40365346143536035 |
oct | 3665457276363023 |
9 | 583175785148777 |
10 | 135624245503507 |
11 | 3a239a12962992 |
12 | 13264a794a8a97 |
13 | 5a8a4083ccb17 |
14 | 256c369c8dc55 |
15 | 10a2d70470a07 |
hex | 7b597af9e613 |
135624245503507 has 2 divisors, whose sum is σ = 135624245503508. Its totient is φ = 135624245503506.
The previous prime is 135624245503477. The next prime is 135624245503511. The reversal of 135624245503507 is 705305542426531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135624245503507 - 239 = 135074489689619 is a prime.
It is not a weakly prime, because it can be changed into another prime (135624245503517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67812122751753 + 67812122751754.
It is an arithmetic number, because the mean of its divisors is an integer number (67812122751754).
Almost surely, 2135624245503507 is an apocalyptic number.
135624245503507 is a deficient number, since it is larger than the sum of its proper divisors (1).
135624245503507 is an equidigital number, since it uses as much as digits as its factorization.
135624245503507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120000, while the sum is 52.
The spelling of 135624245503507 in words is "one hundred thirty-five trillion, six hundred twenty-four billion, two hundred forty-five million, five hundred three thousand, five hundred seven".
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