Base | Representation |
---|---|
bin | 11110110101101100010000… |
… | …100101011110100101011011 |
3 | 122210020012110002222022202011 |
4 | 132311230100211132211123 |
5 | 120234134342412003233 |
6 | 1200244013332450351 |
7 | 40366006604212201 |
oct | 3665542045364533 |
9 | 583205402868664 |
10 | 135631050500443 |
11 | 3a2418951278a3 |
12 | 132662584799b7 |
13 | 5a8ac511ab024 |
14 | 256c813969071 |
15 | 10a311cabb0cd |
hex | 7b5b1095e95b |
135631050500443 has 2 divisors, whose sum is σ = 135631050500444. Its totient is φ = 135631050500442.
The previous prime is 135631050500431. The next prime is 135631050500447. The reversal of 135631050500443 is 344005050136531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135631050500443 - 213 = 135631050492251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135631050500396 and 135631050500405.
It is not a weakly prime, because it can be changed into another prime (135631050500447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67815525250221 + 67815525250222.
It is an arithmetic number, because the mean of its divisors is an integer number (67815525250222).
Almost surely, 2135631050500443 is an apocalyptic number.
135631050500443 is a deficient number, since it is larger than the sum of its proper divisors (1).
135631050500443 is an equidigital number, since it uses as much as digits as its factorization.
135631050500443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 135631050500443 in words is "one hundred thirty-five trillion, six hundred thirty-one billion, fifty million, five hundred thousand, four hundred forty-three".
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