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135631050500443 is a prime number
BaseRepresentation
bin11110110101101100010000…
…100101011110100101011011
3122210020012110002222022202011
4132311230100211132211123
5120234134342412003233
61200244013332450351
740366006604212201
oct3665542045364533
9583205402868664
10135631050500443
113a2418951278a3
12132662584799b7
135a8ac511ab024
14256c813969071
1510a311cabb0cd
hex7b5b1095e95b

135631050500443 has 2 divisors, whose sum is σ = 135631050500444. Its totient is φ = 135631050500442.

The previous prime is 135631050500431. The next prime is 135631050500447. The reversal of 135631050500443 is 344005050136531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135631050500443 - 213 = 135631050492251 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135631050500396 and 135631050500405.

It is not a weakly prime, because it can be changed into another prime (135631050500447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67815525250221 + 67815525250222.

It is an arithmetic number, because the mean of its divisors is an integer number (67815525250222).

Almost surely, 2135631050500443 is an apocalyptic number.

135631050500443 is a deficient number, since it is larger than the sum of its proper divisors (1).

135631050500443 is an equidigital number, since it uses as much as digits as its factorization.

135631050500443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 135631050500443 in words is "one hundred thirty-five trillion, six hundred thirty-one billion, fifty million, five hundred thousand, four hundred forty-three".