Base | Representation |
---|---|
bin | 11001010010000111… |
… | …00100100110010011 |
3 | 1022000222022121111212 |
4 | 30221003210212103 |
5 | 210244332012313 |
6 | 10122523330335 |
7 | 660240403202 |
oct | 145103444623 |
9 | 38028277455 |
10 | 13573704083 |
11 | 5836002865 |
12 | 27699809ab |
13 | 13841c1584 |
14 | 92aa29239 |
15 | 5469c83a8 |
hex | 3290e4993 |
13573704083 has 2 divisors, whose sum is σ = 13573704084. Its totient is φ = 13573704082.
The previous prime is 13573704017. The next prime is 13573704097. The reversal of 13573704083 is 38040737531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13573704083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13573704083.
It is not a weakly prime, because it can be changed into another prime (13573704013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6786852041 + 6786852042.
It is an arithmetic number, because the mean of its divisors is an integer number (6786852042).
Almost surely, 213573704083 is an apocalyptic number.
13573704083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13573704083 is an equidigital number, since it uses as much as digits as its factorization.
13573704083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 13573704083 in words is "thirteen billion, five hundred seventy-three million, seven hundred four thousand, eighty-three".
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