Base | Representation |
---|---|
bin | 10011110000011111001… |
… | …001010111100000111011 |
3 | 11210210112200200211120112 |
4 | 103300133021113200323 |
5 | 134221113421333333 |
6 | 2515422241214535 |
7 | 200043604256504 |
oct | 23603711274073 |
9 | 4723480624515 |
10 | 1357732214843 |
11 | 4838a1491744 |
12 | 19b17993144b |
13 | 9b058a7b604 |
14 | 49a00b97bab |
15 | 254b751b948 |
hex | 13c1f25783b |
1357732214843 has 2 divisors, whose sum is σ = 1357732214844. Its totient is φ = 1357732214842.
The previous prime is 1357732214837. The next prime is 1357732214863. The reversal of 1357732214843 is 3484122377531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1357732214843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1357732214791 and 1357732214800.
It is not a weakly prime, because it can be changed into another prime (1357732214863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678866107421 + 678866107422.
It is an arithmetic number, because the mean of its divisors is an integer number (678866107422).
Almost surely, 21357732214843 is an apocalyptic number.
1357732214843 is a deficient number, since it is larger than the sum of its proper divisors (1).
1357732214843 is an equidigital number, since it uses as much as digits as its factorization.
1357732214843 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3386880, while the sum is 50.
The spelling of 1357732214843 in words is "one trillion, three hundred fifty-seven billion, seven hundred thirty-two million, two hundred fourteen thousand, eight hundred forty-three".
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