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135816124993 is a prime number
BaseRepresentation
bin111111001111101000…
…1011001101001000001
3110222120021000000012121
41332133101121221001
54211122411444433
6142220522524241
712545436004663
oct1763721315101
9428507000177
10135816124993
11526657309aa
12223a4666681
13ca65b40a03
146805ad2533
1537ed779c2d
hex1f9f459a41

135816124993 has 2 divisors, whose sum is σ = 135816124994. Its totient is φ = 135816124992.

The previous prime is 135816124987. The next prime is 135816125017. The reversal of 135816124993 is 399421618531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118520455824 + 17295669169 = 344268^2 + 131513^2 .

It is a cyclic number.

It is not a de Polignac number, because 135816124993 - 213 = 135816116801 is a prime.

It is a super-2 number, since 2×1358161249932 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 135816124993.

It is not a weakly prime, because it can be changed into another prime (135816124943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67908062496 + 67908062497.

It is an arithmetic number, because the mean of its divisors is an integer number (67908062497).

Almost surely, 2135816124993 is an apocalyptic number.

It is an amenable number.

135816124993 is a deficient number, since it is larger than the sum of its proper divisors (1).

135816124993 is an equidigital number, since it uses as much as digits as its factorization.

135816124993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1399680, while the sum is 52.

The spelling of 135816124993 in words is "one hundred thirty-five billion, eight hundred sixteen million, one hundred twenty-four thousand, nine hundred ninety-three".