Base | Representation |
---|---|
bin | 1100010111001000111010… |
… | …1111000100001100100011 |
3 | 1210010100110221022002022222 |
4 | 3011302032233010030203 |
5 | 3240141220313232141 |
6 | 44523532204221255 |
7 | 2601652166142032 |
oct | 305621657041443 |
9 | 53110427262288 |
10 | 13591671227171 |
11 | 4370217089a64 |
12 | 16361a723a82b |
13 | 7778c5c3c47b |
14 | 34dbaa09c719 |
15 | 18883d21514b |
hex | c5c8ebc4323 |
13591671227171 has 2 divisors, whose sum is σ = 13591671227172. Its totient is φ = 13591671227170.
The previous prime is 13591671227011. The next prime is 13591671227201. The reversal of 13591671227171 is 17172217619531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13591671227171 - 230 = 13590597485347 is a prime.
It is not a weakly prime, because it can be changed into another prime (13591671227471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6795835613585 + 6795835613586.
It is an arithmetic number, because the mean of its divisors is an integer number (6795835613586).
Almost surely, 213591671227171 is an apocalyptic number.
13591671227171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13591671227171 is an equidigital number, since it uses as much as digits as its factorization.
13591671227171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1111320, while the sum is 53.
The spelling of 13591671227171 in words is "thirteen trillion, five hundred ninety-one billion, six hundred seventy-one million, two hundred twenty-seven thousand, one hundred seventy-one".
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