Base | Representation |
---|---|
bin | 11110111011000101001110… |
… | …110111000100000010010011 |
3 | 122211112121112202110210010022 |
4 | 132323011032313010002103 |
5 | 120311221443344011024 |
6 | 1201130113115054055 |
7 | 40434532011143006 |
oct | 3673051667040223 |
9 | 584477482423108 |
10 | 136001462485139 |
11 | 3a374995027389 |
12 | 13305bb274132b |
13 | 5ab6b629008b4 |
14 | 25827122c753d |
15 | 10aca9bb1a35e |
hex | 7bb14edc4093 |
136001462485139 has 2 divisors, whose sum is σ = 136001462485140. Its totient is φ = 136001462485138.
The previous prime is 136001462485121. The next prime is 136001462485153. The reversal of 136001462485139 is 931584264100631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136001462485139 - 240 = 134901950857363 is a prime.
It is not a weakly prime, because it can be changed into another prime (136001462485439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68000731242569 + 68000731242570.
It is an arithmetic number, because the mean of its divisors is an integer number (68000731242570).
Almost surely, 2136001462485139 is an apocalyptic number.
136001462485139 is a deficient number, since it is larger than the sum of its proper divisors (1).
136001462485139 is an equidigital number, since it uses as much as digits as its factorization.
136001462485139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 53.
The spelling of 136001462485139 in words is "one hundred thirty-six trillion, one billion, four hundred sixty-two million, four hundred eighty-five thousand, one hundred thirty-nine".
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