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13601553311153 is a prime number
BaseRepresentation
bin1100010111101101101111…
…0000001110010110110001
31210011021222122011222002102
43011323123300032112301
53240321440121424103
644532244535430145
72602452112362353
oct305733360162661
953137878158072
1013601553311153
114374428285a15
1216380a4825355
1377880c382442
143504666c90d3
15188c1aa7ee88
hexc5edbc0e5b1

13601553311153 has 2 divisors, whose sum is σ = 13601553311154. Its totient is φ = 13601553311152.

The previous prime is 13601553311149. The next prime is 13601553311189. The reversal of 13601553311153 is 35111335510631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13074349527409 + 527203783744 = 3615847^2 + 726088^2 .

It is a cyclic number.

It is not a de Polignac number, because 13601553311153 - 22 = 13601553311149 is a prime.

It is a super-2 number, since 2×136015533111532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13601553317153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6800776655576 + 6800776655577.

It is an arithmetic number, because the mean of its divisors is an integer number (6800776655577).

Almost surely, 213601553311153 is an apocalyptic number.

It is an amenable number.

13601553311153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13601553311153 is an equidigital number, since it uses as much as digits as its factorization.

13601553311153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60750, while the sum is 38.

Adding to 13601553311153 its reverse (35111335510631), we get a palindrome (48712888821784).

The spelling of 13601553311153 in words is "thirteen trillion, six hundred one billion, five hundred fifty-three million, three hundred eleven thousand, one hundred fifty-three".