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136029020384593 = 719432717197799
BaseRepresentation
bin11110111011011110111001…
…011100000110110101010001
3122211122020200022112010100001
4132323132321130012311101
5120312144413204301333
61201150511432330001
740436525635341130
oct3673367134066521
9584566608463301
10136029020384593
113a3856468130a6
121330b403843901
135ab963505938b
142583ba8273917
1510ad661153b7d
hex7bb7b9706d51

136029020384593 has 4 divisors (see below), whose sum is σ = 155461737582400. Its totient is φ = 116596303186788.

The previous prime is 136029020384567. The next prime is 136029020384597. The reversal of 136029020384593 is 395483020920631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 136029020384593 - 217 = 136029020253521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136029020384597) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9716358598893 + ... + 9716358598906.

It is an arithmetic number, because the mean of its divisors is an integer number (38865434395600).

Almost surely, 2136029020384593 is an apocalyptic number.

It is an amenable number.

136029020384593 is a deficient number, since it is larger than the sum of its proper divisors (19432717197807).

136029020384593 is an equidigital number, since it uses as much as digits as its factorization.

136029020384593 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19432717197806.

The product of its (nonzero) digits is 8398080, while the sum is 55.

The spelling of 136029020384593 in words is "one hundred thirty-six trillion, twenty-nine billion, twenty million, three hundred eighty-four thousand, five hundred ninety-three".

Divisors: 1 7 19432717197799 136029020384593