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1360330664113 is a prime number
BaseRepresentation
bin10011110010111010000…
…001101010100010110001
311211001020210010201212101
4103302322001222202301
5134241424122222423
62520532143100401
7200165155601401
oct23627201524261
94731223121771
101360330664113
11484a05218083
1219b783ba1701
139b3811ca765
1449ba9d14801
15255ba6e27ad
hex13cba06a8b1

1360330664113 has 2 divisors, whose sum is σ = 1360330664114. Its totient is φ = 1360330664112.

The previous prime is 1360330664089. The next prime is 1360330664129. The reversal of 1360330664113 is 3114660330631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1085747328064 + 274583336049 = 1041992^2 + 524007^2 .

It is a cyclic number.

It is not a de Polignac number, because 1360330664113 - 25 = 1360330664081 is a prime.

It is a super-2 number, since 2×13603306641132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1360330664713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680165332056 + 680165332057.

It is an arithmetic number, because the mean of its divisors is an integer number (680165332057).

Almost surely, 21360330664113 is an apocalyptic number.

It is an amenable number.

1360330664113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360330664113 is an equidigital number, since it uses as much as digits as its factorization.

1360330664113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 37.

Adding to 1360330664113 its reverse (3114660330631), we get a palindrome (4474990994744).

The spelling of 1360330664113 in words is "one trillion, three hundred sixty billion, three hundred thirty million, six hundred sixty-four thousand, one hundred thirteen".