13603412133913 has 4 divisors (see below), whose sum is σ = 15546756724480. Its totient is φ = 11660067543348.

The previous prime is 13603412133893. The next prime is 13603412133919. The reversal of 13603412133913 is 31933121430631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-13603412133913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13603412133919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 971672295273 + ... + 971672295286.

It is an arithmetic number, because the mean of its divisors is an integer number (3886689181120).

Almost surely, 2^{13603412133913} is an apocalyptic number.

It is an amenable number.

13603412133913 is a deficient number, since it is larger than the sum of its proper divisors (1943344590567).

13603412133913 is an equidigital number, since it uses as much as digits as its factorization.

13603412133913 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1943344590566.

The product of its (nonzero) digits is 104976, while the sum is 40.

The spelling of 13603412133913 in words is "thirteen trillion, six hundred three billion, four hundred twelve million, one hundred thirty-three thousand, nine hundred thirteen".